1. Ekadhikena Purvena
This formula means "One More than the Previous One"
1. Squares of Numbers ending in 5
* Fomula is = A(A+1)/25
Where A(A+1) is L.H.S.
and 5^2=25 is R.H.S.
*Now we are applying this.
*Take a example of 25.
*For the number, last (ones place digit) digit is 5 and Previous Digit is 2.
*Now we add one in previous digit that shows 2+1=3
*Procedure 'to multiply the previous digit 2 by one more than itself that is 3.
*It becomes L.H.S
*The R.H.S is 5^2=25
25^2 = (2*3)/25
=625
Problems Based On Formula Ekadhikena Purvena
1. 35^2 = 3*(3+1)/25 = 1225
3. 55^2 = 5*(5+1)/25 = 3025
4. 65^2 = 6*(6+1)/25 = 4225
5. 75^2 = 7*(7+1)/25 = 5625
6. 85^2 = 8*(8+1)/25 = 7225
7. 95^2 = 9*(9+1)/25 = 9025
8. 105^2 = 10*(10+1)/25 = 11025
9. 115^2 = 11*(11+1)/25 = 13225
10. 125^2 = 12*(12+1)/25 = 15625
By this Formula Ekadhikena Purvena we can also find the value of square of
number 135, 145, 155, 165,
Problems Based On Formula Ekadhikena Purvena 2nd
1. 135^2 = 13*(13+1)/25 = 18225
2. 145^2 = 14*(14+1)/25 = 21025
3. 155^2 = 15*(15+1)/25 = 24025
4. 165^2 = 16*(16+1)/25 = 27225
5. 175^2 = 17*(17+1)/25 = 30625
6. 185^2 = 18*(18+1)/25 = 34225
7. 195^2 = 19*(19+1)/25 = 38025
8. 205^2 = 20*(20+1)/25 = 42025
9. 215^2 = 21*(21+1)/25 = 46225
10. 225^2 = 22*(22+1)/25 = 50625
BY this formula we can find the square of number of three digit.
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